2sin^2x+1=0

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Solution for 2sin^2x+1=0 equation: 


Simplifying
2sin2x + 1 = 0

Reorder the terms:
1 + 2in2sx = 0

Solving
1 + 2in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2in2sx = 0 + -1
2in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
2in2sx = -1

Divide each side by '2n2sx'.
i = -0.5n-2s-1x-1

Simplifying
i = -0.5n-2s-1x-1

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